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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceDiagram basedMediumConceptual

JEE Main 29 June 2022, Shift 2, Chemistry Q74

Question 74 of 90 in this shift, Chemistry question 14 of 30, Section A.

[figure: six-membered ring drawn with alternating double bonds] + CH3CH2CH2Cl\mathrm{CH_3CH_2CH_2Cl} → 'A' Major Product (reagent over the arrow: Anhydrous, AlCl3\mathrm{AlCl_3}) The stable carbocation formed in the above reaction is

The figure, in words

Reaction scheme: six-membered ring drawn with alternating double bonds, plus CH3CH2CH2Cl, arrow labelled Anhydrous, AlCl3, giving 'A' (Major Product).
  1. (1)CH3CH2C⊕H2\mathrm{CH_3CH_2\overset{\oplus}{C}H_2}
  2. (2)CH3C⊕H2\mathrm{CH_3\overset{\oplus}{C}H_2}
  3. (3)CH3−C⊕H−CH3\mathrm{CH_3{-}\overset{\oplus}{C}H{-}CH_3}Official answer
  4. (4)[figure: six-membered ring (drawn with alternating double bonds) bearing a CHCH2CH3\mathrm{CHCH_2CH_3} group in which the CH carbon carries a positive charge (circled plus)]

Official answer

Option 3

NTA final key.