JEE Main 2026 · PhysicsNumerical answerNumerical valueMediumApplication

JEE Main 5 April 2026, Shift 1, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

The charged particle moving in a uniform magnetic field of

(3\hat{i} + 2\hat{j})\,\mathrm{T}

has an acceleration

\left(4\hat{i} - \frac{x}{2}\hat{j}\right)\mathrm{m/s^2}

. The value of

x

Official answer

NTA final key.

Chapter: Moving Charges and Magnetism
Topic: Lorentz Force
Idea tested: Magnetic Force Vector Calculation

Same idea in other shifts

Asked 3× in all

2 Apr 2026, Shift 1 · Q48 $1\ \mu$ C charge moving with velocity $\vec v=\left(\hat i-2\hat j+3\hat k\right)$ m/s in the region of magnetic field…EasyNumerical value
8 Jan 2020, Shift 1 · Q12Proton with kinetic energy of 1 MeV moves from south to north. It gets an acceleration of $10^{12}$ m/s $^2$ by an applied magnetic field…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.