JEE Main 2026 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 2 April 2026, Shift 1, Physics Q48

Question 48 of 75 in this shift, Physics question 23 of 25, Section B.

1\ \mu

C charge moving with velocity

\vec v=\left(\hat i-2\hat j+3\hat k\right)

m/s in the region of magnetic field

\vec B=\left(2\hat i+3\hat j-5\hat k\right)

T. The magnitude of force acting on it is

\sqrt\alpha\times10^{-6}

N. The value of

\alpha

is ____________.

Official answer

171

NTA final key.

Chapter: Moving Charges and Magnetism
Topic: Lorentz Force
Idea tested: Magnetic Force Vector Calculation

Same idea in other shifts

Asked 3× in all

5 Apr 2026, Shift 1 · Q49The charged particle moving in a uniform magnetic field of $(3\hat{i} + 2\hat{j})\,\mathrm{T}$ has an acceleration…MediumNumerical value
8 Jan 2020, Shift 1 · Q12Proton with kinetic energy of 1 MeV moves from south to north. It gets an acceleration of $10^{12}$ m/s $^2$ by an applied magnetic field…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.