JEE Main 2026 · PhysicsNumerical answerNumerical valueMediumApplication

JEE Main 2 April 2026, Shift 1, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

A uniform wire of length

l

of weight

w

is suspended from the roof with a weight of

W

at the other end. The stress in the wire at

\frac{l}{3}

distance from the top is

\left(\frac{W}{A}+\frac{2}{\gamma}\frac{w}{A}\right)

, where,

A

is the cross sectional area of the wire. The value of

\gamma

is __________.

Official answer

NTA final key.

Chapter: Mechanical Properties of Solids
Topic: Elasticity
Idea tested: Elongation Due to Self-Weight

Same topic in other shifts

All Elasticity questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.