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Friday, 9 October

JEE Main 2026 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 5 April 2026, Shift 1, Physics Q48

Question 48 of 75 in this shift, Physics question 23 of 25, Section B.

A transverse wave on a string is described by y=3sin⁡(36t+0.018x+π/4)y = 3\sin(36t + 0.018x + \pi/4), where x,yx, y are in cm and tt in seconds. The least distance between the two successive crests in the wave is ____ cm. (Nearest integer) (π=3.14\pi = 3.14)

Official answer

349

NTA final key.

Chapter
Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.