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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2026, Shift 2, Maths Q18

Question 18 of 75 in this shift, Maths question 18 of 25, Section A.

Let f(x)f(x) be a polynomial of degree 5, and have extrema at x=1x = 1 and x=−1x = -1. If lim⁡x→0(f(x)x3)=−5\lim_{x \to 0}\left(\frac{f(x)}{x^3}\right) = -5, then f(2)−f(−2)f(2) - f(-2) is equal to:
  1. (1)00
  2. (2)5050
  3. (3)9292
  4. (4)112112Official answer

Official answer

Option 4

NTA final key.

Same topic in other shifts

All Maxima and Minima questions
  1. 2 Apr 2026, Shift 1 · Q18The number of critical points of the function f(x)={∣sin⁡xx∣,x≠01,x=0f(x)=\begin{cases}\left|\frac{\sin x}{x}\right|, & x\neq0\\ 1, & x=0\end{cases} in the…HardSingle correct
  2. 4 Apr 2026, Shift 2 · Q12max⁡0≤x≤π(16sin⁡(x2)cos⁡3(x2))\max_{0\le x\le\pi}\left(16\sin\left(\frac x2\right)\cos^3\left(\frac x2\right)\right) is equal to:MediumSingle correct
  3. 5 Apr 2026, Shift 1 · Q12The sum of all the integral values of pp such that the equation 3sin⁡2x+12cos⁡x−3=p3\sin^2 x + 12\cos x - 3 = p, x∈Rx \in \mathbb{R}, has at least one…MediumSingle correct
  4. 2 Apr 2025, Shift 1 · Q8If the function f(x)=2x3−9ax2+12a2x+1f(x)=2x^3-9ax^2+12a^2x+1, where a>0a>0, attains its local maximum and local minimum values at p and q, respectively, such…MediumSingle correct
  5. 3 Apr 2025, Shift 2 · Q16Let f:R→Rf: \mathrm{R} \to \mathrm{R} be a function defined by f(x)=∣∣x+2∣−2∣x∣∣f(x) = \left||x+2| - 2|x|\right|. If mm is the number of points of local…MediumSingle correct
  6. 3 Apr 2025, Shift 2 · Q17The shortest distance between the curves y2=8xy^2 = 8x and x2+y2+12y+35=0x^2 + y^2 + 12y + 35 = 0 is:MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.