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Friday, 9 October

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JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2026, Shift 2, Maths Q19

Question 19 of 75 in this shift, Maths question 19 of 25, Section A.

Let

f(x) = \int\frac{16x + 24}{x^2 + 2x - 15}dx

. If

f(4) = 14\log_6(3)

and

f(7) = \log_6(2^{\alpha} \cdot 3^{\beta}), \alpha, \beta \in \mathbb{N}

, then

\alpha + \beta

is equal to:

(1) $31$
(2) $37$
(3) $39$ Official answer
(4) $41$

Official answer

Option 3

NTA final key.

Chapter: Integrals
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.