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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 4 April 2026, Shift 2, Maths Q12

Question 12 of 75 in this shift, Maths question 12 of 25, Section A.

max⁡0≤x≤π(16sin⁡(x2)cos⁡3(x2))\max_{0\le x\le\pi}\left(16\sin\left(\frac x2\right)\cos^3\left(\frac x2\right)\right) is equal to:
  1. (1)332\frac{3\sqrt3}{2}
  2. (2)333\sqrt3Official answer
  3. (3)434\sqrt3
  4. (4)636\sqrt3

Official answer

Option 2

NTA final key.