JEE Main 2022 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 25 July 2022, Shift 1, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A.

If the absolute maximum value of the function

f(x)=(x^2-2x+7)\,\mathrm{e}^{(4x^3-12x^2-180x+31)}

in the interval

[-3,0]

f(\alpha)

, then :

(1) $\alpha=0$
(2) $\alpha=-3$ Official answer
(3) $\alpha\in(-1,0)$
(4) $\alpha\in(-3,-1]$

Official answer

Option 2

NTA final key (2022 Session 2).

Chapter: Application of Derivatives
Topic: Maxima and Minima
Idea tested: Closed Interval Extrema

Same idea in other shifts

Asked 5× in all

4 Apr 2026, Shift 2 · Q12 $\max_{0\le x\le\pi}\left(16\sin\left(\frac x2\right)\cos^3\left(\frac x2\right)\right)$ is equal to:MediumSingle correct
7 Apr 2025, Shift 1 · Q17Let $x = -1$ and $x = 2$ be the critical points of the function $f(x) = x^3 + ax^2 + b\log_e|x| + 1$ , $x \neq 0$ . Let $m$ and $M$ …MediumSingle correct
30 Jan 2024, Shift 2 · Q9Let $f(x) = (x+3)^2 (x-2)^3$ , $x \in [-4, 4]$ . If $M$ and $m$ are the maximum and minimum values of $f$ , respectively in $[-4, 4]$ , then…MediumSingle correct
24 Jun 2022, Shift 1 · Q12The sum of absolute maximum and absolute minimum values of the function $f(x)=|2x^2+3x-2|+\sin x\cos x$ in the interval $[0, 1]$ is :HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.