JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 7 April 2025, Shift 2, Physics Q35

Question 35 of 75 in this shift, Physics question 10 of 25, Section A.

The equation of a wave travelling on a string is

y=\sin[20\pi x+10\pi t]

, where

x

and t are distance and time in SI units. The minimum distance between two points having the same oscillating speed is :

(1)2.5 cm
(2)5.0 cmOfficial answer
(3)10 cm
(4)20 cm

Official answer

Option 2

NTA final key.

Chapter: Waves
Topic: Waves on Strings
Idea tested: Particle Velocity vs Wave Velocity

Same idea in other shifts

Asked 3× in all

2 Apr 2026, Shift 1 · Q35The equation of a plane progressive wave is given by $y=5\cos\pi\left(200\,t-\frac{x}{150}\right)$ where $x$ and $y$ are in cm and $t$ is…EasySingle correct
29 Jun 2022, Shift 1 · Q46A longitudinal wave is represented by $x = 10\sin 2\pi\left(nt - \frac{x}{\lambda}\right)$ cm. The maximum particle velocity will be four…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.