JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 26 July 2022, Shift 2, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

A transverse wave is represented by

y = 2\sin(\omega t - kx)

cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be :

(1) $4\pi$ Official answer
(2) $2\pi$
(3) $\pi$
(4)2

Official answer

Option 1

NTA final key.

Chapter: Waves
Topic: Waves on Strings
Idea tested: Particle Velocity vs Wave Velocity

Same idea in other shifts

Asked 4× in all

2 Apr 2026, Shift 1 · Q35The equation of a plane progressive wave is given by $y=5\cos\pi\left(200\,t-\frac{x}{150}\right)$ where $x$ and $y$ are in cm and $t$ is…EasySingle correct
7 Apr 2025, Shift 2 · Q35The equation of a wave travelling on a string is $y=\sin[20\pi x+10\pi t]$ , where $x$ and t are distance and time in SI units. The minimum…MediumSingle correct
29 Jun 2022, Shift 1 · Q46A longitudinal wave is represented by $x = 10\sin 2\pi\left(nt - \frac{x}{\lambda}\right)$ cm. The maximum particle velocity will be four…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.