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Friday, 9 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 29 June 2022, Shift 1, Physics Q46

Question 46 of 90 in this shift, Physics question 16 of 30, Section A.

A longitudinal wave is represented by x=10sin⁡2π(nt−xλ)x = 10\sin 2\pi\left(nt - \frac{x}{\lambda}\right) cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to :
  1. (1)2π2\pi
  2. (2)5π5\piOfficial answer
  3. (3)π\pi
  4. (4)5π2\frac{5\pi}{2}

Official answer

Option 2

NTA final key (2022 Session 1).

Chapter
Waves