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Friday, 9 October

JEE Main 2025 · ChemistryMultiple choiceDiagram basedEasyData or graph

JEE Main 4 April 2025, Shift 2, Chemistry Q55

Question 55 of 75 in this shift, Chemistry question 5 of 25, Section A.

Consider the following plots of log of rate constant k (log k) vs 1T\frac{1}{T} for three different reactions. The correct order of activation energies of these reactions is :

The figure, in words

Plot of log k (y-axis) vs 1/T (x-axis) with three straight lines of negative slope: line 1 has a moderate slope, line 2 is nearly vertical (steepest), line 3 is nearly flat (gentlest).
  1. (1)Ea2>Ea1>Ea3\mathrm{Ea_2>Ea_1>Ea_3}Official answer
  2. (2)Ea1>Ea2>Ea3\mathrm{Ea_1>Ea_2>Ea_3}
  3. (3)Ea3>Ea2>Ea1\mathrm{Ea_3>Ea_2>Ea_1}
  4. (4)Ea1>Ea3>Ea2\mathrm{Ea_1>Ea_3>Ea_2}

Official answer

Option 1

NTA final key.

Chapter
Chemical Kinetics
Topic
Arrhenius Equation
Idea tested
Log Base 10 Arrhenius Plot Slope

Same topic in other shifts

All Arrhenius Equation questions
  1. 2 Apr 2026, Shift 1 · Q74For reaction A→P\mathrm{A\rightarrow P}, rate constant k=1.5×103 s−1k=1.5\times10^3\ \mathrm{s^{-1}} at 27∘27^\circC If activation energy for the above…MediumNumerical value
  2. 6 Apr 2026, Shift 2 · Q75Decomposition of a hydrocarbon follows the equation k=(5.5×1011 s−1) e−28000 KTk=(5.5\times10^{11}\,\mathrm{s^{-1}})\,e^{\frac{-28000\,\mathrm{K}}{T}}. The…EasyNumerical value
  3. 8 Apr 2026, Shift 2 · Q57Given below are two statements : R=8.314 J K−1 mol−1R = 8.314\ \mathrm{J\,K^{-1}\,mol^{-1}} and 1 cal = 4.2 J Statement I : When Ea = 12.6 kcal/mol, the…MediumTwo statementsHas a figure
  4. 2 Apr 2025, Shift 2 · Q56Reactant A converts to product D through the given mechanism (with the net evolution of heat) : A→BA \rightarrow B slow; ΔH=+\Delta H = +ve…MediumDiagram basedHas a figure
  5. 3 Apr 2025, Shift 2 · Q57Consider the following statements related to temperature dependence of rate constants. Identify the correct statements. A. The Arrhenius…MediumOther
  6. 29 Jan 2024, Shift 1 · Q87For a reaction taking place in three steps at same temperature, overall rate constant K=K1K2K3K=\frac{K_1K_2}{K_3}. If Ea1Ea_1, Ea2Ea_2 and Ea3Ea_3…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.