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Saturday, 31 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumData or graph

JEE Main 25 February 2021, Shift 1, Chemistry Q56

Question 56 of 90 in this shift, Chemistry question 26 of 30, Section B.

For the reaction, aA+bB→cC+dDa\mathrm{A} + b\mathrm{B} \rightarrow c\mathrm{C} + d\mathrm{D}, the plot of log⁡k\log k vs 1T\frac{1}{\mathrm{T}} is given below : The temperature at which the rate constant of the reaction is 10−410^{-4} s−1^{-1} is ________ K. (Rounded-off to the nearest integer) [Given : The rate constant of the reaction is 10−510^{-5} s−1^{-1} at 500 K.]

The figure, in words

Graph with vertical axis labelled log k (arrow upward) and horizontal axis labelled 1/T (arrow to the right). A straight line starts high on the vertical axis and slopes downward to the right, labelled 'slope = -10000 K'. No numeric tick values.

Official answer

526

NTA final key.