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Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceDiagram basedMediumMulti-step

JEE Main 2 April 2025, Shift 2, Physics Q42

Question 42 of 75 in this shift, Physics question 17 of 25, Section A.

Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is V. The potential difference between the points A and B (shown in the figure) is :

The figure, in words

Two vertical parallel conducting plates 10 cm apart, each connected by a horizontal wire to a terminal dot. Between them, point C lies on a horizontal line (perpendicular to the plates), point A is 3 cm directly above C, and point B is on the horizontal line to the right of C; AB = 5 cm (dashed). Right-angle mark at C.
  1. (1)14\frac{1}{4} V
  2. (2)25\frac{2}{5} VOfficial answer
  3. (3)34\frac{3}{4} V
  4. (4)11 V

Official answer

Option 2

NTA final key.

Chapter
Electrostatic Potential and Capacitance
Topic
Electric Potential
Idea tested
Equipotential Planes of Uniform Field

Same topic in other shifts

All Electric Potential questions
  1. 6 Apr 2026, Shift 2 · Q37The electric potential as a function of x,yx, y is given by V=5(x2−y2)V=5(x^2-y^2) V. The electric field at a point (2, 3) m is __________ V/m.EasySingle correct
  2. 6 Apr 2026, Shift 2 · Q40A sphere of capacitance 100 pF is charged to a potential of 100 V. Another identical uncharged metal sphere is brought in contact with the…MediumSingle correct
  3. 3 Apr 2025, Shift 1 · Q39The electrostatic potential on the surface of uniformly charged spherical shell of radius R = 10 cm is 120 V. The potential at the centre…EasySingle correct
  4. 7 Apr 2025, Shift 1 · Q38Two charges q1q_1 and q2q_2 are separated by a distance of 30 cm. A third charge q3q_3 initially at 'C' as shown in the figure, is moved…MediumDiagram basedHas a figure
  5. 8 Apr 2025, Shift 2 · Q35Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Work done in moving a…EasyAssertion–reason
  6. 9 Apr 2024, Shift 1 · Q55At the centre of a half ring of radius R=10R=10 cm and linear charge density 4 nC m−14\ \mathrm{nC\,m^{-1}}, the potential is xπx\pi V. The value…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.