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Friday, 9 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 9 April 2024, Shift 1, Physics Q55

Question 55 of 90 in this shift, Physics question 25 of 30, Section B.

At the centre of a half ring of radius R=10R=10 cm and linear charge density 4 nC m−14\ \mathrm{nC\,m^{-1}}, the potential is xπx\pi V. The value of xx is ________.

Official answer

36

NTA final key.