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Friday, 9 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 3 April 2025, Shift 1, Physics Q39

Question 39 of 75 in this shift, Physics question 14 of 25, Section A.

The electrostatic potential on the surface of uniformly charged spherical shell of radius R = 10 cm is 120 V. The potential at the centre of shell, at a distance r = 5 cm from centre, and at a distance r = 15 cm from the centre of the shell respectively, are:
  1. (1)40V, 40V, 80V
  2. (2)0V, 120V, 40V
  3. (3)120V, 120V, 80VOfficial answer
  4. (4)0V, 0V, 80V

Official answer

Option 3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2025, Shift 2 · Q35Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Work done in moving a…EasyAssertion–reason

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.