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JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 31 January 2024, Shift 1, Physics Q47

Question 47 of 90 in this shift, Physics question 17 of 30, Section A.

If the wavelength of the first member of Lyman series of hydrogen is

\lambda

. The wavelength of the second member will be

(1) $\frac{27}{32}\lambda$ Official answer
(2) $\frac{32}{27}\lambda$
(3) $\frac{27}{5}\lambda$
(4) $\frac{5}{27}\lambda$

Official answer

Option 1

NTA final key.

Chapter: Atoms
Topic: Bohr's Atomic Model
Idea tested: Rydberg Formula and Spectra

Same idea in other shifts

Asked 2× in all

5 Apr 2026, Shift 1 · Q36In the hydrogen atom, the electron makes a transition from the higher orbit ( $i$ ) to a lower orbit ( $f$ ). The ratio of the radius of the…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.