Learn

Friday, 9 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 31 January 2024, Shift 1, Physics Q46

Question 46 of 90 in this shift, Physics question 16 of 30, Section A.

When a metal surface is illuminated by light of wavelength λ\lambda, the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3λ3\lambda, stopping potential is 2V. The threshold wavelength for this surface is:
  1. (1)4.5λ4.5\lambda
  2. (2)3λ3\lambda
  3. (3)5λ5\lambda
  4. (4)9λ9\lambdaOfficial answer

Official answer

Option 4

NTA final key.