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Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 5 April 2026, Shift 1, Physics Q36

Question 36 of 75 in this shift, Physics question 11 of 25, Section A.

In the hydrogen atom, the electron makes a transition from the higher orbit (ii) to a lower orbit (ff). The ratio of the radius of the orbits in given by ri:rf=16:4r_i : r_f = 16 : 4. The wavelength of photon emitted due to this transition is ________ nm. (Given Rydberg constant =1.0973×107= 1.0973 \times 10^7 /m)
  1. (1)121
  2. (2)242
  3. (3)486Official answer
  4. (4)974

Official answer

Option 3

NTA final key.

Chapter
Atoms
Topic
Bohr's Atomic Model
Idea tested
Rydberg Formula and Spectra

Same idea in other shifts

Asked 2× in all
  1. 31 Jan 2024, Shift 1 · Q47If the wavelength of the first member of Lyman series of hydrogen is λ\lambda. The wavelength of the second member will beEasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.