JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 31 January 2024, Shift 1, Physics Q32

Question 32 of 90 in this shift, Physics question 2 of 30, Section A.

The relation between time 't' and distance 'x' is

t=\alpha x^2+\beta x

, where

\alpha

and

\beta

are constants. The relation between acceleration

(a)

and velocity

(v)

is :

(1) $a=-2\alpha v^3$ Official answer
(2) $a=-3\alpha v^2$
(3) $a=-4\alpha v^4$
(4) $a=-5\alpha v^5$

Official answer

Option 1

NTA final key.

Chapter: Motion in a Straight Line
Topic: Kinematics in 1D
Idea tested: Implicit Time-Position Equations

Same topic in other shifts

All Kinematics in 1D questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.