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JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 31 January 2024, Shift 1, Physics Q31

Question 31 of 90 in this shift, Physics question 1 of 30, Section A.

A force is represented by

F=ax^2+bt^{\frac{1}{2}}

where

x

= distance and

t

= time. The dimensions of

b^2/a

are:

(1) $[MLT^{-2}]$
(2) $[ML^{-1}T^{-1}]$
(3) $[ML^{2}T^{-3}]$
(4) $[ML^{3}T^{-3}]$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Units and Measurements
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.