JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 2 April 2026, Shift 1, Physics Q28

Question 28 of 75 in this shift, Physics question 3 of 25, Section A.

The velocity of a particle is given as

\vec v=-x\hat i+2y\hat j-z\hat k

m/s. The magnitude of acceleration at point

(1, 2, 4)

is __________

\mathrm{m/s^2}

(1) $\sqrt6$
(2) $9$ Official answer
(3) $\sqrt{33}$
(4) $0$

Official answer

Option 2

NTA final key.

Chapter: Motion in a Plane
Topic: Kinematics in 1D
Idea tested: Position-Dependent Acceleration (v dv/dx)

Same topic in other shifts

All Kinematics in 1D questions

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2 Apr 2025, Shift 1 · Q49A person travelling on a straight line moves with a uniform velocity $v_1$ for a distance $x$ and with a uniform velocity $v_2$ for the…EasyNumerical value
2 Apr 2025, Shift 2 · Q30A sportsman runs around a circular track of radius $r$ such that he traverses the path ABAB. The distance travelled and displacement,…EasySingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.