JEE Main 2024 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 1 February 2024, Shift 1, Chemistry Q85

Question 85 of 90 in this shift, Chemistry question 25 of 30, Section B.

The potential for the given half cell at 298 K is

(-)

________

\times 10^{-2}\,\mathrm{V}

\mathrm{2H^+_{(aq)} + 2e^- \longrightarrow H_2(g)}

\mathrm{[H^+] = 1M,\ P_{H_2} = 2\ atm}

(Given :

2.303RT/F = 0.06\ \mathrm{V}

\log 2 = 0.3

)

Official answer

NTA final key.

Chapter: Electrochemistry
Topic: Nernst Equation
Idea tested: Nernst Equation for Gas Electrodes

Same topic in other shifts

All Nernst Equation questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.