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JEE Main 2026 · ChemistryMultiple choiceSingle correctMediumApplication

JEE Main 8 April 2026, Shift 2, Chemistry Q56

Question 56 of 75 in this shift, Chemistry question 6 of 25, Section A.

Given at 298 K :

E^{\ominus}_{\mathrm{Fe^{2+}/Fe}} = X

Volt

E^{\ominus}_{\mathrm{Fe^{3+}/Fe}} = Y

Volt The

E^{\ominus}_{\mathrm{Fe^{3+}/Fe^{2+}}}

in Volt at 298 K is given by :

(1) $2X - 3Y$
(2) $3Y - 2X$ Official answer
(3) $3Y + 2X$
(4) $Y + X$

Official answer

Option 2

NTA final key.

Chapter: Electrochemistry
Topic: Nernst Equation
Idea tested: Latimer Diagrams and E0

Same idea in other shifts

Asked 2× in all

11 Apr 2023, Shift 1 · Q86In an electrochemical reaction of lead, at standard temperature, if $\mathrm{E^{\circ}(Pb^{2+}/Pb)} = m$ Volt and…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.