JEE Main 2023 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 11 April 2023, Shift 1, Chemistry Q86

Question 86 of 90 in this shift, Chemistry question 26 of 30, Section B.

In an electrochemical reaction of lead, at standard temperature, if

\mathrm{E^{\circ}(Pb^{2+}/Pb)} = m

Volt and

\mathrm{E^{\circ}(Pb^{4+}/Pb)} = n

Volt, then the value of

\mathrm{E^{\circ}(Pb^{2+}/Pb^{4+})}

is given by

m - xn

. The value of x is __________. (Nearest integer)

Official answer

NTA final key.

Same idea in other shifts