JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 9 April 2024, Shift 2, Physics Q51

Question 51 of 90 in this shift, Physics question 21 of 30, Section B.

A force

(3x^2+2x-5)

N displaces a body from

x=2

m to

x=4

m. Work done by this force is ___________ J.

Official answer

NTA final key.

Chapter: Work, Energy and Power
Topic: Work and Kinetic Energy
Idea tested: Work by Variable Force

Same idea in other shifts

Asked 3× in all

3 Apr 2025, Shift 2 · Q31A block of mass 1 kg, moving along $x$ with speed $v_i = 10$ m/s enters a rough region ranging from $x = 0.1$ m to $x = 1.9$ m. The…MediumSingle correct
11 Apr 2023, Shift 1 · Q59A force $\vec{F} = (2 + 3x)\hat{i}$ acts on a particle in the $x$ direction where F is in newton and $x$ is in meter. The work done by…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.