JEE Main 2023 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 11 April 2023, Shift 1, Physics Q59

Question 59 of 90 in this shift, Physics question 29 of 30, Section B.

A force

\vec{F} = (2 + 3x)\hat{i}

acts on a particle in the

x

direction where F is in newton and

x

is in meter. The work done by this force during a displacement from

x = 0

x = 4

m, is _________J.

Official answer

NTA final key.

Chapter: Work, Energy and Power
Topic: Work and Kinetic Energy
Idea tested: Work by Variable Force

Same idea in other shifts

Asked 3× in all

3 Apr 2025, Shift 2 · Q31A block of mass 1 kg, moving along $x$ with speed $v_i = 10$ m/s enters a rough region ranging from $x = 0.1$ m to $x = 1.9$ m. The…MediumSingle correct
9 Apr 2024, Shift 2 · Q51A force $(3x^2+2x-5)$ N displaces a body from $x=2$ m to $x=4$ m. Work done by this force is ___________ J.EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.