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Friday, 9 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 April 2024, Shift 2, Physics Q50

Question 50 of 90 in this shift, Physics question 20 of 30, Section A.

The magnetic field in a plane electromagnetic wave is By=(3.5×10−7)sin⁡(1.5×103x+0.5×1011t)TB_y=(3.5\times10^{-7})\sin(1.5\times10^3x+0.5\times10^{11}t)\mathrm{T}. The corresponding electric field will be :
  1. (1)Ey=1.17sin⁡(1.5×103x+0.5×1011t) Vm−1E_y=1.17\sin(1.5\times10^3x+0.5\times10^{11}t)\ \mathrm{Vm^{-1}}
  2. (2)Ey=10.5sin⁡(1.5×103x+0.5×1011t) Vm−1E_y=10.5\sin(1.5\times10^3x+0.5\times10^{11}t)\ \mathrm{Vm^{-1}}
  3. (3)Ez=105sin⁡(1.5×103x+0.5×1011t) Vm−1E_z=105\sin(1.5\times10^3x+0.5\times10^{11}t)\ \mathrm{Vm^{-1}}Official answer
  4. (4)Ez=1.17sin⁡(1.5×103x+0.5×1011t) Vm−1E_z=1.17\sin(1.5\times10^3x+0.5\times10^{11}t)\ \mathrm{Vm^{-1}}

Official answer

Option 3

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.