JEE Main 2024 · PhysicsNumerical answerNumerical valueHardMulti-step

JEE Main 9 April 2024, Shift 1, Physics Q60

Question 60 of 90 in this shift, Physics question 30 of 30, Section B.

A star has

100\%

helium composition. It starts to convert three

{}^4\mathrm{He}

into one

{}^{12}\mathrm{C}

via triple alpha process as

{}^4\mathrm{He}+{}^4\mathrm{He}+{}^4\mathrm{He}\to{}^{12}\mathrm{C}+Q

. The mass of the star is

2.0\times10^{32}

kg and it generates energy at the rate of

5.808\times10^{30}

W. The rate of converting these

{}^4\mathrm{He}

{}^{12}\mathrm{C}

n\times10^{42}\ \mathrm{s^{-1}}

, where n is ________. [ Take, mass of

{}^4\mathrm{He}=4.0026

u, mass of

{}^{12}\mathrm{C}=12

Official answer

NTA final key.

Chapter: Nuclei
Topic: Fission and Fusion
Idea tested: Q-Value of a Reaction

Same topic in other shifts

All Fission and Fusion questions

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.