JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 9 April 2024, Shift 1, Physics Q59

Question 59 of 90 in this shift, Physics question 29 of 30, Section B.

In a Young's double slit experiment, the intensity at a point is

\left(\frac{1}{4}\right)^{th}

of the maximum intensity, the minimum distance of the point from the central maximum is ________

\mu

m. (Given :

\lambda=600

nm,

d=1.0

mm,

D=1.0

Official answer

200

NTA final key.

Chapter: Wave Optics
Topic: Young's Double Slit
Idea tested: Intensity at Fractional Path Differences

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.