JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 6 September 2020, Shift 2, Physics Q24

Question 24 of 75 in this shift, Physics question 24 of 25.

A Young's double-slit experiment is performed using monochromatic light of wavelength

\lambda

. The intensity of light at a point on the screen, where the path difference is

\lambda

, is K units. The intensity of light at a point where the path difference is

\frac{\lambda}{6}

is given by

\frac{nK}{12}

, where n is an integer. The value of n is ________.

Official answer

9.00

NTA final key (Sep 2020).

Chapter: Wave Optics
Topic: Young's Double Slit
Idea tested: Intensity at Fractional Path Differences

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.