JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyApplication

JEE Main 9 April 2024, Shift 1, Chemistry Q61

Question 61 of 90 in this shift, Chemistry question 1 of 30, Section A.

Compare the energies of following sets of quantum numbers for multielectron system. (A)

n=4, l=1

(B)

n=4, l=2

(C)

n=3, l=1

(D)

n=3, l=2

(E)

n=4, l=0

Choose the correct answer from the options given below :

(1)(E) > (C) > (A) > (D) > (B)
(2)(C) < (E) < (D) < (A) < (B)Official answer
(3)(E) < (C) < (D) < (A) < (B)
(4)(B) > (A) > (C) > (E) > (D)

Official answer

Option 2

NTA final key.

Chapter: Structure of Atom
Topic: Quantum Numbers
Idea tested: Aufbau Principle and n+l Rule

Same idea in other shifts

Asked 4× in all

4 Apr 2026, Shift 1 · Q53Which of the following is correct set of $4$ quantum numbers of $19^{\text{th}}$ electron in Chromium (Atomic number $=24$ ) in accordance…MediumSingle correct
5 Apr 2026, Shift 1 · Q52Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. A. $n = 3, l = 2, m = +1$ B.…MediumOther
5 Apr 2026, Shift 2 · Q52Which of the following statement(s) is/are true ? A. If two orbitals have the same value of $(n+l)$ , the orbital with lower value of n…MediumOther

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.