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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 April 2024, Shift 1, Maths Q20

Question 20 of 90 in this shift, Maths question 20 of 30, Section A.

Let ∣cos⁡θcos⁡(60∘−θ)cos⁡(60∘+θ)∣≤18\left|\cos\theta\cos(60^\circ-\theta)\cos(60^\circ+\theta)\right|\le\frac{1}{8}, θ∈[0,2π]\theta\in[0,2\pi]. Then, the sum of all θ∈[0,2π]\theta\in[0,2\pi], where cos⁡3θ\cos3\theta attains its maximum value, is :
  1. (1)6π6\piOfficial answer
  2. (2)18π18\pi
  3. (3)9π9\pi
  4. (4)15π15\pi

Official answer

Option 1

NTA final key.

Same topic in other shifts

All Trigonometric Identities questions
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  2. 2 Apr 2026, Shift 2 · Q13Let P={θ∈[0,4π]:tan⁡2θ≠1}P = \{\theta \in [0, 4\pi]: \tan^2\theta \ne 1\} and…MediumSingle correct
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  4. 5 Apr 2026, Shift 1 · Q6Let tan⁡A\tan A, tan⁡B\tan B, where A,B∈(−π2,π2)A, B \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right), be the roots of the quadratic equation…MediumSingle correct
  5. 8 Apr 2026, Shift 2 · Q22If…HardNumerical value
  6. 4 Apr 2025, Shift 2 · Q3Let the product of ω1=(8+i)sin⁡θ+(7+4i)cos⁡θ\omega_1=(8+i)\sin\theta+(7+4i)\cos\theta and ω2=(1+8i)sin⁡θ+(4+7i)cos⁡θ\omega_2=(1+8i)\sin\theta+(4+7i)\cos\theta be α+iβ\alpha+i\beta,…HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.