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Friday, 9 October

JEE Main 2026 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 4 April 2026, Shift 1, Maths Q23

Question 23 of 75 in this shift, Maths question 23 of 25, Section B.

If A=sin⁡3∘cos⁡9∘+sin⁡9∘cos⁡27∘+sin⁡27∘cos⁡81∘A=\frac{\sin 3^\circ}{\cos 9^\circ}+\frac{\sin 9^\circ}{\cos 27^\circ}+\frac{\sin 27^\circ}{\cos 81^\circ} and B=tan⁡81∘−tan⁡3∘B=\tan 81^\circ-\tan 3^\circ, then BA\frac{B}{A} is equal to ______.

Official answer

2

NTA final key.