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Friday, 9 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 1, Maths Q6

Question 6 of 75 in this shift, Maths question 6 of 25, Section A.

Let tan⁡A\tan A, tan⁡B\tan B, where A,B∈(−π2,π2)A, B \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right), be the roots of the quadratic equation x2−2x−5=0x^2 - 2x - 5 = 0. Then 20sin⁡2(A+B2)20\sin^2\left(\frac{A+B}{2}\right) is equal to:
  1. (1)10+1010+\sqrt{10}
  2. (2)10−21010-2\sqrt{10}
  3. (3)10−31010-3\sqrt{10}Official answer
  4. (4)10−1010-\sqrt{10}

Official answer

Option 3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 30 Jan 2024, Shift 2 · Q11For α,β∈(0,π/2)\alpha, \beta \in (0, \pi/2), let 3sin⁡(α+β)=2sin⁡(α−β)3\sin(\alpha + \beta) = 2\sin(\alpha - \beta) and a real number kk be such that…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.