JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 8 April 2024, Shift 1, Physics Q57

Question 57 of 90 in this shift, Physics question 27 of 30, Section B.

An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3

\mu

T perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that electron moves along the same path, is ______

\mathrm{NC^{-1}}

. (Given, mass of electron

=9\times10^{-31}

kg, electric charge

=1.6\times10^{-19}

Official answer

NTA final key.

Chapter: Moving Charges and Magnetism
Topic: Lorentz Force
Idea tested: Velocity Selector and Crossed Fields

Same topic in other shifts

All Lorentz Force questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.