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Friday, 9 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 6 April 2024, Shift 2, Physics Q58

Question 58 of 90 in this shift, Physics question 28 of 30, Section B.

A coil having 100 turns, area of 5×10−3 m25\times10^{-3}\ \mathrm{m^2}, carrying current of 1 mA is placed in uniform magnetic field of 0.20 T such a way that plane of coil is perpendicular to the magnetic field. The work done in turning the coil through 90∘90^\circ is ________ μJ\mu\mathrm{J}.

Official answer

100

NTA final key.