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Friday, 9 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 6 April 2024, Shift 2, Physics Q57

Question 57 of 90 in this shift, Physics question 27 of 30, Section B.

A particle moves in a straight line so that its displacement xx at any time tt is given by x2=1+t2x^2=1+t^2. Its acceleration at any time tt is x−nx^{-n} where n=n= ________.

Official answer

3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 3 Apr 2025, Shift 2 · Q28A particle moves along the xx-axis and has its displacement xx varying with time t according to the equation:…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.