JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 26 June 2022, Shift 2, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

A bar magnet having a magnetic moment of

2.0 \times 10^{5}\ JT^{-1}

, is placed along the direction of uniform magnetic field of magnitude B=

14 \times 10^{-5}\ T

. The work done in rotating the magnet slowly through

60^\circ

from the direction of field is :

(1)14 JOfficial answer
(2)8.4 J
(3)4 J
(4)1.4 J

Official answer

Option 1

NTA final key.

Chapter: Magnetism and Matter
Topic: Magnetic Dipole Moment
Idea tested: Work done in rotating a dipole

Same idea in other shifts

Asked 5× in all

4 Apr 2024, Shift 2 · Q43The magnetic moment of a bar magnet is 0.5 Am $^2$ . It is suspended in a uniform magnetic field of $8\times10^{-2}$ T. The work done in…EasySingle correct
6 Apr 2024, Shift 1 · Q57A circular coil having 200 turns, $2.5\times10^{-4}$ m $^2$ area and carrying 100 $\mu$ A current is placed in a uniform magnetic field of…EasyNumerical value
6 Apr 2024, Shift 2 · Q58A coil having 100 turns, area of $5\times10^{-3}\ \mathrm{m^2}$ , carrying current of 1 mA is placed in uniform magnetic field of 0.20 T…EasyNumerical value
4 Sep 2020, Shift 1 · Q14A small bar magnet placed with its axis at 30° with an external field of 0.06 T experiences a torque of 0.018 Nm. The minimum work…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.