JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 4 April 2024, Shift 2, Physics Q41

Question 41 of 90 in this shift, Physics question 11 of 30, Section A.

A charge

q

is placed at the center of one of the surface of a cube. The flux linked with the cube is:

(1) $\frac{q}{2\epsilon_0}$ Official answer
(2) $\frac{q}{4\epsilon_0}$
(3) $\frac{q}{8\epsilon_0}$
(4)Zero

Official answer

Option 1

NTA final key.

Chapter: Electric Charges and Fields
Topic: Gauss's Law
Idea tested: Flux via Cube Symmetry

Same idea in other shifts

Asked 3× in all

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25 Feb 2021, Shift 2 · Q9A charge ‘q’ is placed at one corner of a cube as shown in figure. The flux of electrostatic field $\vec{E}$ through the shaded area is :MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.