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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyRecall

JEE Main 4 April 2024, Shift 2, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

The translational degrees of freedom (ftf_t) and rotational degrees of freedom (frf_r) of CH4CH_4 molecule are:
  1. (1)ft=3f_t = 3 and fr=2f_r = 2
  2. (2)ft=2f_t = 2 and fr=3f_r = 3
  3. (3)ft=3f_t = 3 and fr=3f_r = 3Official answer
  4. (4)ft=2f_t = 2 and fr=2f_r = 2

Official answer

Option 3

NTA final key.