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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 24 February 2021, Shift 2, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

A point charge of +12 μC+12\ \mu\mathrm{C} is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be __________ ×103 Nm2/C\times 10^3\ \mathrm{Nm^2/C}.

The figure, in words

A point charge labelled +q (dot) at the top, joined by a vertical thick line down to a dot at the centre of a tilted square drawn in perspective (a rhombus-like outline); a double-headed vertical arrow beside the line is labelled 6 cm; two adjacent sides of the square are each labelled 12 cm.

Official answer

226

NTA final key.

Chapter
Electric Charges and Fields
Topic
Gauss's Law
Idea tested
Flux via Cube Symmetry

Same idea in other shifts

Asked 3× in all
  1. 4 Apr 2024, Shift 2 · Q41A charge qq is placed at the center of one of the surface of a cube. The flux linked with the cube is:MediumSingle correct
  2. 25 Feb 2021, Shift 2 · Q9A charge ‘q’ is placed at one corner of a cube as shown in figure. The flux of electrostatic field E⃗\vec{E} through the shaded area is :MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.