JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 13 April 2023, Shift 2, Physics Q41

Question 41 of 90 in this shift, Physics question 11 of 30, Section A.

10\ \mu

C charge is divided into two parts and placed at

1

cm distance so that the repulsive force between them is maximum. The charges of the two parts are:

(1) $8\ \mu\mathrm{C}, 2\ \mu\mathrm{C}$
(2) $7\ \mu\mathrm{C}, 3\ \mu\mathrm{C}$
(3) $5\ \mu\mathrm{C}, 5\ \mu\mathrm{C}$ Official answer
(4) $9\ \mu\mathrm{C}, 1\ \mu\mathrm{C}$

Official answer

Option 3

NTA final key.

Chapter: Electric Charges and Fields
Topic: Coulomb's Law
Idea tested: Maximizing Force via Charge Division

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.