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JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 13 April 2023, Shift 2, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

A particle executes SHM of amplitude A. The distance from the mean position when its's kinetic energy becomes equal to its potential energy is:

(1) $2A$
(2) $\frac{1}{2}A$
(3) $\frac{1}{\sqrt{2}}A$ Official answer
(4) $\sqrt{2A}$

Official answer

Option 3

NTA final key.

Chapter: Oscillations
Topic: Energy in SHM
Idea tested: Kinetic to Potential Energy Ratio

Same idea in other shifts

Asked 2× in all

29 Jan 2024, Shift 1 · Q54When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.