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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 27 July 2022, Shift 2, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

A charge of 4 μ\muC is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be :
  1. (1)1 μ\muC and 3 μ\muC
  2. (2)2 μ\muC and 2 μ\muCOfficial answer
  3. (3)0 and 4 μ\muC
  4. (4)1.5 μ\muC and 2.5 μ\muC

Official answer

Option 2

NTA final key.

Chapter
Electric Charges and Fields
Topic
Coulomb's Law
Idea tested
Maximizing Force via Charge Division

Same idea in other shifts

Asked 2× in all
  1. 13 Apr 2023, Shift 2 · Q41A 10 μ10\ \muC charge is divided into two parts and placed at 11 cm distance so that the repulsive force between them is maximum. The…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.