JEE Main 12 April 2023, Shift 1, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A.

\frac{1}{n+1}{}^{n}\mathrm{C}_{n}+\frac{1}{n}{}^{n}\mathrm{C}_{n-1}+\ldots+\frac{1}{2}{}^{n}\mathrm{C}_{1}+{}^{n}\mathrm{C}_{0}=\frac{1023}{10}

then

n

is equal to

(1) $6$
(2) $7$
(3) $8$
(4) $9$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Binomial Theorem
Topic: Binomial Coefficients
Idea tested: Integration Method for Sums

Same idea in other shifts

Asked 3× in all

8 Apr 2026, Shift 2 · Q8If…HardSingle correct
29 Jan 2024, Shift 1 · Q23If $\frac{{}^{11}C_1}{2}+\frac{{}^{11}C_2}{3}+\ldots+\frac{{}^{11}C_9}{10}=\frac{n}{m}$ with $\gcd(n,m)=1$ , then $n+m$ is equal to ______.MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.