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Friday, 9 October

JEE Main 2024 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 29 January 2024, Shift 1, Maths Q23

Question 23 of 90 in this shift, Maths question 23 of 30, Section B.

If 11C12+11C23+…+11C910=nm\frac{{}^{11}C_1}{2}+\frac{{}^{11}C_2}{3}+\ldots+\frac{{}^{11}C_9}{10}=\frac{n}{m} with gcd⁡(n,m)=1\gcd(n,m)=1, then n+mn+m is equal to ______.

Official answer

2041

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2026, Shift 2 · Q8If…HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.