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Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceDiagram basedEasyData or graph

JEE Main 8 April 2023, Shift 1, Physics Q50

Question 50 of 90 in this shift, Physics question 20 of 30, Section A.

Graphical variation of electric field due to a uniformly charged insulating solid sphere of radius R, with distance r from the centre O is represented by:

The figure, in words

Circle (solid sphere) with centre O and an arrow along radius R. Option graphs have axes E and r with r=R marked by a dashed vertical line.
  1. (1)[figure: graph of E vs r, E rises linearly from origin to a peak at r=R (dashed lines to axes), then decreases as a curve (inverse-square type) for r>R]Official answer
  2. (2)[figure: graph of E vs r, E constant (horizontal) up to r=R, then decreases as a curve for r>R]
  3. (3)[figure: graph of E vs r, E rises as a curve from origin up to r=R, then constant (horizontal) for r>R]
  4. (4)[figure: graph of E vs r, E rises as a curve from origin to a peak at r=R, then decreases linearly for r>R]

Official answer

Option 1

NTA final key.

Chapter
Electric Charges and Fields
Topic
Gauss's Law
Idea tested
Nonconducting Sphere

Same topic in other shifts

All Gauss's Law questions
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  5. 4 Apr 2024, Shift 2 · Q41A charge qq is placed at the center of one of the surface of a cube. The flux linked with the cube is:MediumSingle correct
  6. 6 Apr 2024, Shift 1 · Q38σ\sigma is the uniform surface charge density of a thin spherical shell of radius RR. The electric field at any point on the surface of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.