JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 26 July 2022, Shift 1, Physics Q37

Question 37 of 90 in this shift, Physics question 7 of 30, Section A.

In a series LR circuit

X_L = R

and power factor of the circuit is

P_1

. When capacitor with capacitance C such that

X_L = X_C

is put in series, the power factor becomes

P_2

. The ratio

\frac{P_1}{P_2}

is :

(1) $\frac{1}{2}$
(2) $\frac{1}{\sqrt{2}}$ Official answer
(3) $\frac{\sqrt{3}}{\sqrt{2}}$
(4) $2:1$

Official answer

Option 2

NTA final key.

Chapter: Alternating Current
Topic: Phasor Diagrams
Idea tested: Power Factor from Phasors

Same idea in other shifts

Asked 9× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.